- x and n are input through keyboard.Write a program to compute xn, n!, nCr, nPr
xn
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int x,n,res=1;
int i;
printf("Enter the value of x?\n");
scanf("%d",&x);
printf("Enter the value of n?\n");
scanf("%d",&n);
for(i=0;i<n;i++)
res=res*x;
printf("Answer:%d",res);
getch();
}
n!
#include<stdio.h>
#include<conio.h>
void main()
{
int n,i,
res=1;
clrscr();
printf("Enter the n=");
scanf("%d",&n);
for(i=n;i>=1;i--)
res=res*i;
printf("n!=%d",res);
getch();
}nCr
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
long int n,r,sum=1,i,k,p,res=1,x,rem=1,f,ncr;
printf("Enter the value of n:");
scanf("%ld",&n);
printf("Enter the value of r:");
scanf("%ld",&r);
p=n-r;
for(i=n;i>=1;i--)
{
sum=sum*i;
}
for(k=p;k>=1;k--)
{
res=res*k;
}
for(x=r;x>=1;x--)
{
rem=rem*x;
}
f=res*rem;
ncr=sum/f;
printf("\nncr=%ld",ncr);
getch();
}
nPr#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
long int n,r,sum=1,i,k,p,res=1,l;
printf("Enter the value of n:");
scanf("%ld",&n);
printf("Enter the value of r:");
scanf("%ld",&r);
p=n-r;
for(i=n;i>=1;i--)
sum=sum*i;
for(k=p;k>=1;k--)
{
res=res*k;
}
l=sum/res;
printf("\nnpr=%ld",l);
getch();
} - Write a program to determine the GCD and LCM of 3 numbers.
GCD#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int a,b,c,rem;
printf("Enter the value of a?\n");
scanf("%d",&a);
printf("Enter the value of b?\n");
scanf("%d",&b);
printf("Enter the value of c?\n");
scanf("%d",&c);
while(b>0)
{
rem=a%b;
a=b;
b=rem;
}
while(c>0)
{
rem=a%c;
a=c;
c=rem;
}
printf("GCD is:%d",a);
getch();
}
LCM
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int a,b,c,i;
printf("Enter the value of a?\n");
scanf("%d",&a);
printf("Enter the value of b?\n");
scanf("%d",&b);
printf("Enter the value of c?\n");
scanf("%d",&c);
for(i=1; ;i++)
{
if(i%a==0&&i%b==0&&i%c==0)
break;
}
printf("LCM is:\n%d",i);
getch();
} - Find out the sum of each of the following series. n is the input from user for series (4)
- 3+11+19+.........+1691.
- 7+20+33+.........(up to 100th term)
- 5-11+17-..........(up to 75th term)
- 2*7*12*...........*37
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
long int x=3,sum=0;
for(x=3;x<=1691;x=x+8)
{
sum=sum+x;
}
printf("\n\nSUM:%ld",sum);
getch();
}
2.
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
long int x=7,sum=0,i;
for(i=1;i<=100;i++)
{
sum=sum+x;
x=x+13;
}
printf("\n\nSUM:%ld",sum);
getch();
}
3.
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
long int x=5,sum=0,i;
for(i=1;i<=75;i++)
{
sum=sum+x;
if(x>0)
x=(x+6)*-1;
else
x=(x-6)*-1;
}
printf("\n\nSUM:%ld",sum);
getch();
}.
4.
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
long int x=2,sum=1;
for(x=2;x<=37;x=x+5)
{
sum=sum*x;
}
printf("\n\nSUM:%ld",sum);
getch();
} - Write a program to determine all prime numbers within the range [a.......b]
where a & b are input through keyboard.
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int num,num1,i,n,l;
scanf("%d",&num);
scanf("%d",&num1);
n=2;
l=num;
for(i=l;i<=num1;i++)
{
while(n<=i/2)
{
if(i%n==0)
break;
++n;
}
if(n>i/2 && i!=2)
printf(" %d",i);
n=2;
}
getch();
} - Construct the following table.Here n is input from the user.
1 2 3 ..... n
2 4 6 ....... 2n
3 6 9 ....... 3n
. . . ..... .
. . . ....... .
. . . ....... .
n 2n 3n ....... nn
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,n,k;
scanf("%d",&n);
for(i=1;i<=n;i++)
{
for(k=1;k<=n;k++)
printf("\t%d",k*i);
printf("\n");
}
getch();
} - Write a program to find out first n perfect number where n is the input from user.
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,num,sum=0;
printf("Enter a num");
scanf("%d",&num);
for(i=1;i<=num/2;i++)
if(num%i==0)
sum=sum+i;
if(sum==num)
printf("The number is a perfect number");
else
printf("The number is not a perfect number");
getch();
} - Write a program to find first n Fibonacci number where n is the input from user.
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int n,a,b,sum,i,rem;
a=0;
b=1;
printf("Enter the value of n?\n");
scanf("%d",&n);
printf("The fibonacci numbers are:");
for(i=1;i<=n;i++)
{
sum=a+b;
rem=sum;
a=b;
b=rem;
printf("\n%d\n",sum);
}
getch();
} - Write a program to show the following triangle/rectangle of "*" or numbers.Take n as inpute from user to determine the number of rows of the structure.(eg. n=5)
1.
#include<stdio.h>
#include<conio.h>
void main() { clrscr();
int i,k,n;
scanf("%d",&n);
int c=1;
int s=n-1;
for(i=1;i<=n;i++)
{
for(k=1;k<=s;k++)
printf(" ");
s--;
for(k=1;k<=c;k++)
printf("*");
c=c+2;
printf("\n");
}
getch();
}
2.
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,k,n;
scanf("%d",&n);
int c=1;
int s=n-1;
for(i=1;i<=n;i++)
{
for(k=1;k<=s;k++)
printf(" ");
s--;
for(k=1;k<=c;k++)
if(k==1||k==c)
printf("*");
else if(i==n)
printf("*");
else
printf(" ");
c=c+2;
printf("\n");
}
getch();
}
4.
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,k,n;
scanf("%d",&n);
int c=1;
int s=n-1;
for(i=1;i<=n;i++)
{
for(k=1;k<=s;k++)
printf("*");
for(k=1;k<=c;k++)
printf("*");
c=c;
printf("\n");
}
getch();
}
5.
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,n,k;
scanf("%d",&n);
for(i=1;i<=n;i++)
{
for(k=1;k<=n;k++)
{ if(k==1||k==n)
printf("*");
else if(i==1||i==n)
printf("*");
else
printf(" ");
}
printf("\n");
}
getch();
}
7.
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,k,n;
scanf("%d",&n);
int c=1;
int s=n-1;
for(i=1;i<=n;i++)
{
for(k=1;k<=s;k++)
printf(" ");
s--;
for(k=1;k<=c;k++)
printf("*");
c=c+2;
printf("\n");
}
c=c-4;
s=1;
for(i=1;i<=n;i++)
{
for(k=1;k<=s;k++)
printf(" ");
s++;
for(k=1;k<=c;k++)
printf("*");
c=c-2;
printf("\n");
}
getch();
}
8.
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,k,n;
scanf("%d",&n);
int c=1;
int s=n-1;
for(i=1;i<=n;i++)
{
for(k=1;k<=s;k++)
printf(" ");
s--;
for(k=1;k<=c;k++)
printf("*");
c=c+2;
printf("\n");
}
c=c-4;
s=1;
for(i=1;i<=n;i++)
{
for(k=1;k<=s;k++)
printf(" ");
s++;
for(k=1;k<=c;k++)
printf("*");
c=c-2;
printf("\n");
}
getch();
}
10.
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,k,n;
scanf("%d",&n);
int c=(2*n)-1;
int s=0;
for(i=1;i<=n;i++)
{
for(k=1;k<=s;k++)
printf(" ");
s++;
for(k=1;k<=c;k++)
printf("*");
c=c-2;
printf("\n");
}
c=3;
s=n-2;
n=n-1;
for(i=1;i<=n;i++)
{
for(k=1;k<=s;k++)
printf(" ");
s--;
for(k=1;k<=c;k++)
printf("*");
c=c+2;
printf("\n");
}
getch();
} - Write a program to print out all Armstrong numbers between 1 and 10000.
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int num,sum=0,k,rem,i;
for(i=1;i<=10000;i++)
{
num=i;
sum=0;
for(k=1;k<=i;k++)
{
rem=num%10;
sum=sum+(rem*rem*rem);
num=num/10;
}
if(sum==i)
printf("\n%d\n",i);
}
getch();
} - Write a program to calculate how many 5 digit numbers can be created if the following terms apply:
- the leftmost digit is even
- the second digit is odd
- the third digit is a non even prime
- the fourth and fifth are two random digits not used before in the number.
#include<stdio.h>
#include<conio.h>
long int prime(long int n);
void main()
{
clrscr();
long int a,b,c,d,e,i,rem,num,count=0;
for(i=20000;i<=99999;i++)
{
rem=i%10;
e=rem;
num=i/10;
rem=num%10;
d=rem;
num=num/10;
rem=num%10;
c=rem;
num=num/10;
rem=num%10;
b=rem;
num=num/10;
a=num;
if(a%2==0&&b%2!=0&&prime(c)&&d!=a&&d!=b&&d!=c&&e!=d&&e!=a&&e!=b&&e!=c)
count++;
}
printf(" \nRESULT=%ld",count);
getch();
}
long int prime (long int n)
{ int m;
m=2;
while(m<=n/2)
{
if(n%m==0)
break;
++m;
}
if(m>n/2&&n!=2&&n!=1&&n!=0)
return 1;
else
return 0;
}
Wednesday, March 30, 2011
Looping C programming
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